7x^2+56x-22=0

Solution for 7x^2+56x-22=0 equation:

7x^2+56x-22=0

a = 7; b = 56; c = -22;
Δ = b2-4ac
Δ = 562-4·7·(-22)
Δ = 3752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3752}=\sqrt{4*938}=\sqrt{4}*\sqrt{938}=2\sqrt{938}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-2\sqrt{938}}{2*7}=\frac{-56-2\sqrt{938}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+2\sqrt{938}}{2*7}=\frac{-56+2\sqrt{938}}{14}
$